Mathematical Proof that Expulsion of Propellant Causes Temperature Decrease
Basis : as we expel mass, the mass component Mg goes down, and so does mass fraction. Beginning with three assumptions:
• Definition of Mass Fraction is valid : x = yg / yg+yf, where y is a state property such as internal energy. This is the basis for linear interpolation and is valid.
• Definition of Internal Energy says U is proportional to T : U = u(T)
• Relation of Specific Internal Energy: U = Mu.
1. Mu=U
2. MT[uf + x(ug-uf)] = U
3. x = Mg/Mg+Mf ჻ (Mg+Mf) [uf +(Mg/Mg+Mf)(ug-uf)]
4. (Mg+Mf)uf + [(Mg+Mf)/(Mg+Mf)] Mgug - [(Mg+Mf)/(Mg+Mf)] Mguf
5. (Mg+Mf)uf + Mgug – Mguf = U
6. mf→constant, uf→constant, ug→constant, ჻ (ug-uf) →constant.
7. (Mg+A)B + Mg( C ) = U
8. BMg + AB + MgC = U
9. Mg(B+C) +AB = U
჻Since Mg↓ as X↓, and A, B, C are all constants, the sums and products (B+C) and AB are also constant. Therefore if Mg↓, so must U. And U is proportional to T,
჻ Mg↓ ჻ U ↓ ჻ T↓.
NOTE: Sorry, the subscripts don't show up as subscripts. Any variable like "Mg" is supposed to be M with a subscript g to indicate "Mass of gas", or "MT" meaning... I forget
